I'm trying to evaluate an integral of a rational function, but I'm wondering if the following step is correct:

$\displaystyle \[\frac{x^2}{\left (x^2-9 \right )^2}=\frac{1/3}{x+3}+\frac{1/4}{\left (x+3 \right )^2}+\frac{1/2}{x-3}+\frac{1/4}{\left ( x-3 \right )^2}\]$