Given ( 1 , 4 ) is a turning point of the curve y = ax^3 + bx^2 - 6x - 1/2 .

Find the values of a and b

(Wondering)

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- Jul 17th 2010, 06:57 AMZharif93turning point of a curve
Given ( 1 , 4 ) is a turning point of the curve y = ax^3 + bx^2 - 6x - 1/2 .

Find the values of a and b

(Wondering) - Jul 17th 2010, 07:16 AMeumyang
If (1, 4) is on the curve , plug in x and y to get

If (1, 4) is a turning point, then the derivative of y is 0 at that point:

You're left with a system of equations

Solve for a and b.