Well, we can rewrite as . Now
Im really confused with the way my texbook explains the answer to this question:
lim as x approaches 0 of (5^x- 3^x)/x
So clearly thats impossible since there cant be a 0 in the denomintor so we use L'hospital's rule. Now the back of my textbook uses ln and this is where it got me confused:
lim (5^x- 3^x)/x = lim (5^xln5- 3^xln3)/1
I thought the general log rule was ln5^x = xln5 not 5^xln5 ???