Hi all, I have to do this problem according to the first part of the Fundamental Theorem of Calculus. Fundamental theorem of calculus - Wikipedia, the free encyclopedia

h(x)= (integral of 0 to x^2) sqrt(1+r^3) dr

answer:

f(x)=sqrt(1+r^3)

h'(x)=f(x)

h'(x)=sqrt(1+x^6)* 2x

Am I right? I was kind of confused, also did I miss any steps? Thanks!