Hi, just want to double check my answers and how it is set up! My prof. grades HW very harshly :/
V(t)=t^2-2t-8 1(<=) t (<=) 6
I did this using definite integrals.
Thanks
I did the problem wrong. I think I have it now
I know the difference between displacement and distance is that you have the absolute sign for distance. But in this case it doesn't matter since both integrals are positive. Am I right? Thanks
the answer for displacement is 22.3 m
and for distance, it is also 22.3 m