Thread: Evaluate the indefinite integral

I can't seem to figure out how to integrate

2x
---- dx ?
x-4

I tried U substitution for both 2x and x-4 but to no avail

Originally Posted by nottheface

I can't seem to figure out how to integrate

2x
---- dx ?
x-4

I tried U substitution for both 2x and x-4 but to no avail

Hint:

Another way to do the same thing: substitute u= x- 4 as you did. Then x= u+ 4 so 2x= 2u+ 8. du= dx and the integral becomes