If the linear density is constant, then you can just use the formula , where is the mass, and is the length of the wire. Where would you go from there?
A thin wire is bent into the shape of a semicircle x^2+y^2=4 x>0
If the linear density is 3, find the mass of the wire.
Anyone have a clue how to tackle this problem?
Thanks for your help
Possible answers -
18pi
6pi^2
3pi
6pi
2pi
ok ok you win, lol (duh about the 18pi! thats what happens when 20 vector calc problems are running through your head.)
(180/360)*((2(pi)*2)=6.28
6.28*3=18.84
6*pi=18.84
Thanks for your help, I really appreciate it!
-Anson