A thin wire is bent into the shape of a semicircle x^2+y^2=4 x>0
If the linear density is 3, find the mass of the wire.
Anyone have a clue how to tackle this problem?
Thanks for your help(Happy)
Possible answers -
18pi
6pi^2
3pi
6pi
2pi
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A thin wire is bent into the shape of a semicircle x^2+y^2=4 x>0
If the linear density is 3, find the mass of the wire.
Anyone have a clue how to tackle this problem?
Thanks for your help(Happy)
Possible answers -
18pi
6pi^2
3pi
6pi
2pi
If the linear densityis constant, then you can just use the formula
, where
is the mass, and
is the length of the wire. Where would you go from there?
Well it looks like now I need to find the length of the curve of wire.
Correct. And how could you find the length of a semicircle?
So I just graphed it and cheated a bit and just ruffed out the length of the curve by the Pythagorean theorem and I got the curve to be ~ 6 so 3*6= 18
So the answer is 6pi?
Thanks again Adrian!
You can get the exact answer (which is not, by the way). What's the length of a wire that's in the shape of a circle?
ok ok you win, lol (duh about the 18pi! thats what happens when 20 vector calc problems are running through your head.)
(180/360)*((2(pi)*2)=6.28
6.28*3=18.84
6*pi=18.84
Thanks for your help, I really appreciate it!
-Anson
You're very welcome.
By the way, "pie" is what you eat. "pi" is the standard transliteration of.
lol........ I knew that I just didn't think about it as I never write pi out in words.