Find the value of b if the vertical line x=b divides the region between y=16-2x, x-axis and y-axis into equal areas.
i got the area between 0 and 8 to be 64 but from there i am lost.
Define $\displaystyle g(y)= \int_0 ^y (16-2x)dx$ and put $\displaystyle A=g(8)$ be the total area. Now just solve $\displaystyle g(y)=\frac{1}{2}A$ which should be a quadratic in $\displaystyle y$.