Differentiate 1 / (t+3e^t)

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Jul 11th 2010, 03:42 PM
superduper1

Differentiate 1 / (t+3e^t)

By using the quotient rule, I get -3e^t for the numerator.
The problem is the denominator: (t+3e^t)^2

I don't believe I'm foiling the denominator correctly.
Jul 11th 2010, 10:40 PM
red_dog

$\left(\displaystyle\frac{1}{t+3e^t}\right)'=-\displaystyle\frac{(t+3e^t)'}{(t+3e^t)^2}=-\displaystyle\frac{1+3e^t}{(t+3e^t)^2}$

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