By using the quotient rule, I get -3e^t for the numerator.

The problem is the denominator: (t+3e^t)^2

I don't believe I'm foiling the denominator correctly.

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- Jul 11th 2010, 03:42 PMsuperduper1Differentiate 1 / (t+3e^t)
By using the quotient rule, I get -3e^t for the numerator.

The problem is the denominator: (t+3e^t)^2

I don't believe I'm foiling the denominator correctly. - Jul 11th 2010, 10:40 PMred_dog
$\displaystyle \left(\displaystyle\frac{1}{t+3e^t}\right)'=-\displaystyle\frac{(t+3e^t)'}{(t+3e^t)^2}=-\displaystyle\frac{1+3e^t}{(t+3e^t)^2}$