the endpoint comes -1 and 1 and I am taking the integral of ((9/8)-x^2)-(x^2/8)....and then multiplyig by 2pi. the final answers come 3pi. Any help thanks
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method of washers ... $\displaystyle \displaystyle V = \pi \int_a^b [R(x)]^2 - [r(x)]^2 \, dx$
Originally Posted by skeeter method of washers ... $\displaystyle \displaystyle V = \pi \int_a^b [R(x)]^2 - [r(x)]^2 \, dx$ so its like this with end points of -1 and 1
Originally Posted by racewithferrari so its like this with end points of -1 and 1 second term in the integrand should be $\displaystyle \left(\frac{x^2}{8}\right)^2$ if what you posted originally is correct ... $\displaystyle \frac{x^2}{8} \ne \frac{1}{8x^2}$ also ... limits of integration?
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