Prove: If is continius function on and if , then is bounded on What I did.. I looked the next two intervals: 1. , is bounded there. 2. , and I don't know what to do next here... Thanks!
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Originally Posted by Also sprach Zarathustra Prove: If is continius function on and if , then is bounded on What I did.. I looked the next two intervals: 1. , is bounded there. 2. , and I don't know what to do next here... Thanks! Use the definition of , taking . It tells you that there exists N such that whenever x>N. So f is bounded on . But it is also bounded on [0,N] ... .
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