1. ## Instantaneous Velocity

Find the instantaneous velocity of $sin(2x)$ at $x=1$.

I tried applying the definition of derivative at a point and then using trig identities (double angle, sum), but what I ended up, zero, with didn't make sense. How should this be calculated?

Thanks

2. f'(x)=m=2cos(2x)

f'(1)=2cos2

3. Instructor wants me to use the definition of derivative at a point, not a derivative formula.

4. Originally Posted by cribby
Instructor wants me to use the definition of derivative at a point, not a derivative formula.
Derivative of sin x - An approach to calculus

5. Originally Posted by cribby
Find the instantaneous velocity of $sin(2x)$ at $x=1$.

[snip]
That makes no sense. Go back and check the question. Is it meant to be x = sin(2t)?