How to you show the series sigma n^(3/n) converge or diverge?
Should i use the com parsing test?
Last edited by mr fantastic; Jul 7th 2010 at 09:49 PM.
Reason: Copied title into main body of post.
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Read the section on "Ratio Test" Pauls Online Notes : Calculus II - Ratio Test
ratio test is inconclusive with this case since lim n->inf n^[(3/n+1)-3/n] =1
The series fails the -th term test.
Originally Posted by de20 should i use the com parsing test? Since the series is clearly divergent by the limit test.
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