How to you show the series sigma n^(3/n) converge or diverge?

Should i use the com parsing test?(Headbang)

- Jul 7th 2010, 09:01 PMde20how to you show the series sigma n^(3/n) converge or diverge?
How to you show the series sigma n^(3/n) converge or diverge?

Should i use the com parsing test?(Headbang) - Jul 7th 2010, 09:09 PMpickslides
Read the section on "Ratio Test"

Pauls Online Notes : Calculus II - Ratio Test - Jul 7th 2010, 09:15 PMde20
ratio test is inconclusive with this case since lim n->inf n^[(3/n+1)-3/n] =1

- Jul 7th 2010, 09:46 PMroninpro
The series fails the $\displaystyle n$-th term test.

$\displaystyle \lim_{n\to \infty} n^{3/n}=1$ - Jul 7th 2010, 09:47 PMmr fantastic