Factor,

x^2+10x-39=(x-3)(x+13)

x - 2 = (x+2) - 4B) Lim x-2/(squareroot of x+2)-2

x to 2

Difference of two squares,

[sqrt(x+2) - 2 ]*[sqrt(x+2) + 2]

Now cancel numerator and denominator.

Divide numerator and denominator by x^2C) lim 2x^2-5x+3/5x^2-6

x to infinity

(2 - 5/x + 3/x^2)/ (5 - 6/x^2)

As x---> BIG

We have,

(2-0+0)/(5-0)