Equation has exactly 2 solutions

$\displaystyle m(x+1)=e^{|x|}$

Find $\displaystyle m\in\mathbb{R}$ so that the equation has exactly two solutions. I really don't know where to start... but for that equation to have any solutions $\displaystyle m(x+1)$ has to be positive and non-zero.

One answer from below is corect:

$\displaystyle A) m\in(1,\infty)$

$\displaystyle B) m\in(-\infty,-e^2)\cup(1,\infty)$

$\displaystyle C) m\in(-\infty,-e^2]\cup[1,\infty)$

$\displaystyle D) m\in(-\infty,-e^2)\cup(0,1)$

$\displaystyle E) m\in{\O}$

F) none of the above