Hi,
Can anyone help me with the following question?
I have to integrate 2sinxcosx Lower limit 0 Upper limit 2
Do I alter 2sinxcosx to sin2x before integrating or do I integrate 2sinxcosx?
Thanks
Cromlix
Either way is fine.
If you convert $\displaystyle 2\sin{x}\cos{x}$ to $\displaystyle \sin{2x}$ you would use a $\displaystyle u$ substitution with $\displaystyle u = 2x$.
If you keep it as $\displaystyle 2\sin{x}\cos{x}$ then you would use a $\displaystyle u$ substitution either with $\displaystyle u = \sin{x}$ or $\displaystyle u = \cos{x}$.