I am stuck with this question. I have to calculate the limit
my formula is .. This is final value theorem of Z transform
f(infinity) = limit (z-->1) [ 1- z^ -1] x [ 1/( 1+ z^ -2]
How to solve this
second is
f(infinity) = limit (z-->1) [ 1- z^ -1] x [ z / (( z-1/2) (z-2))]
I am pasting the question
Its solution for Inverse Z transform code is also pasted.
num=[0 1 0]
den=[1 -5/2 1]
x=[1 zeros(1,10)]
y=filter(num,den,x)
If we solve it with inversion integral then answer comes to be
2/3 [2^k - (1/2)^k]
which mean it is ascending continuously
Its initial value is zero which is correct but final value should be infinity
The formula for final value is
x(infinity)= limit (z--->1) (1-1/z) F(z)