Results 1 to 4 of 4

Math Help - Integration problem

  1. #1
    Member
    Joined
    Oct 2009
    Posts
    114
    Thanks
    1

    Integration problem

     <br />
\[\int tan^3(x) sec^4(x) dx\]<br />

    I first tried substituting \[u = tan(x)\], then I tried substituting \[u = sec(x)\], but I couldn't seem to solve it.

    Any hints?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Jun 2009
    Posts
    806
    Thanks
    4
    Quote Originally Posted by BrownianMan View Post
     <br />
\[\int tan^3(x) sec^4(x) dx\]<br />

    I first tried substituting \[u = tan(x)\], then I tried substituting \[u = sec(x)\], but I couldn't seem to solve it.

    Any hints?
    \int tan^3(x)sec^4(x) cab be written as

    \int tan^3(x)sec^2(x)sec^2(x)

    \int tan^3(x)[1 + tan^2(x)]sec^2(x)

    Now simplify and solve.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    May 2010
    From
    Texas
    Posts
    48
    tan^2(x)+1=sec^2(x)
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Member
    Joined
    Oct 2009
    Posts
    114
    Thanks
    1
    Thank you!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. integration problem
    Posted in the Calculus Forum
    Replies: 4
    Last Post: October 21st 2010, 07:19 AM
  2. Integration problem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: September 20th 2010, 06:46 PM
  3. Replies: 2
    Last Post: February 19th 2010, 11:55 AM
  4. Integration Problem
    Posted in the Calculus Forum
    Replies: 3
    Last Post: August 2nd 2009, 04:35 PM
  5. Integration problem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: April 21st 2008, 11:11 PM

Search Tags


/mathhelpforum @mathhelpforum