lim (1-cos 2x) / 3x x->0 i think the answer is 0, can someone explain how to solve this?
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Originally Posted by viet lim (1-cos 2x) / 3x x->0 i think the answer is 0, can someone explain how to solve this? Rewrite as, (1-cos 2x) / (2x) * (2/3) Now the first factor is zero because of the famous limit, lim (x-->0) (1-cos 2x)/2x =0
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