Hi there, I must solve this:
The statement says that I must solve it using an adequate trigonometric substitution.
I followed this way:
I've used the identity:
There must be an easier way yo solve this.
sh and ch are the hyperbolic function, sinh(t) and cosh(t)?
One other method would be to use trig functions rather than hyperbolic functions. Since , dividing both sides by , . That suggests using the substitution . I doubt that that is any simpler but most people are more familiar with trig functions than with hyperbolic functions.
Thanks HallsofIvy. I thought of that too, but it was easier to memorize the hyperbolic substitutions to me, and I did all those kind of integrations using hyperbolic substitutions when I could, and in the others. I think you're right, but I'm not much familiarized with trigonometric identities, unless not much more than what I am with hyperbolic identities. But I'll try that way.
Bye there.
Oh, BTW
The answer is yes :POriginally Posted by HallsofIvy