Hi there, I must solve this:

The statement says that I must solve it using an adequate trigonometric substitution.

I followed this way:

I've used the identity:

There must be an easier way yo solve this.

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- Jun 29th 2010, 04:42 PMUlyssesSolving an integral using ash substitution
Hi there, I must solve this:

The statement says that I must solve it using an adequate trigonometric substitution.

I followed this way:

I've used the identity:

There must be an easier way yo solve this. - Jun 29th 2010, 06:03 PMHallsofIvy
sh and ch are the hyperbolic function, sinh(t) and cosh(t)?

One other method would be to use trig functions rather than hyperbolic functions. Since , dividing both sides by , . That suggests using the substitution . I doubt that that is any simpler but most people are more familiar with trig functions than with hyperbolic functions. - Jun 29th 2010, 06:16 PMUlysses
Thanks HallsofIvy. I thought of that too, but it was easier to memorize the hyperbolic substitutions to me, and I did all those kind of integrations using hyperbolic substitutions when I could, and in the others. I think you're right, but I'm not much familiarized with trigonometric identities, unless not much more than what I am with hyperbolic identities. But I'll try that way.

Bye there.

Oh, BTW

Quote:

Originally Posted by**HallsofIvy**

- Jun 29th 2010, 07:42 PMProve It
- Jun 30th 2010, 06:18 AMHallsofIvy
But notice in the original post, "The statement says that I must solve it using an adequate

**trigonometric**substitution". (Emphasis mine.) - Jun 30th 2010, 09:09 PMProve It