Thread: Instantaneous Velocity

If a rock is thrown upward on the moon with a velocity of 58 m/s, its height in meters after t seconds is given by

H = 58t - 0.83t^2.

Find the instantaneous velocity after 1 second (round to tenths).




How do I approach this problem, guys?

The "instantaneous velocity" is the derivative of the height function.

Ahhhh. So I take the derivative and get 58-1.66t, correct? And then substitute 1, giving me 56.34, or 56.3 since we're rounding. Does that look right?

Looks good.