If a rock is thrown upward on the moon with a velocity of 58 m/s, its height in meters after t seconds is given by

H = 58t - 0.83t^2.

Find the instantaneous velocity after 1 second (round to tenths).

How do I approach this problem, guys?

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- Jun 29th 2010, 11:02 AMbobsanchezInstantaneous Velocity
If a rock is thrown upward on the moon with a velocity of 58 m/s, its height in meters after t seconds is given by

H = 58t - 0.83t^2.

Find the instantaneous velocity after 1 second (round to tenths).

How do I approach this problem, guys? - Jun 29th 2010, 11:14 AMHallsofIvy
The "instantaneous velocity" is the

**derivative**of the height function. - Jun 29th 2010, 02:10 PMbobsanchez
Ahhhh. So I take the derivative and get 58-1.66t, correct? And then substitute 1, giving me 56.34, or 56.3 since we're rounding. Does that look right?

- Jun 29th 2010, 02:38 PMMattMan
Looks good.