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Thread: Derivatives- inverse trig

  1. May 13th 2007, 10:46 PM #1
    ClipsClips99
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    Derivatives- inverse trig

    Hi, I need help on two problems regarding derivatives of inverse trigonometric functions
    Find the derivative f'(x)

    A) f(x)= [arccos(x^2)]^(-2)

    b) f(x) = log( arccos[1/sqrt(x)] )

    Thanks in advance
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  2. May 13th 2007, 10:53 PM #2
    qbkr21
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    Re:

    Quote Originally Posted by ClipsClips99 View Post
    Hi, I need help on two problems regarding derivatives of inverse trigonometric functions
    Find the derivative f'(x)

    A) f(x)= [arccos(x^2)]^(-2)

    b) f(x) = log( arccos[1/sqrt(x)] )

    Thanks in advance
    RE:
    Attached Thumbnails Attached Thumbnails Derivatives- inverse trig-6.gif  
    Last edited by qbkr21; May 14th 2007 at 08:31 AM.
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