Hi, I need help on two problems regarding derivatives of inverse trigonometric functions

Find the derivative f'(x)

A) f(x)= [arccos(x^2)]^(-2)

b) f(x) = log( arccos[1/sqrt(x)] )

Thanks in advance

Printable View

- May 13th 2007, 11:46 PMClipsClips99Derivatives- inverse trig
Hi, I need help on two problems regarding derivatives of inverse trigonometric functions

Find the derivative f'(x)

A) f(x)= [arccos(x^2)]^(-2)

b) f(x) = log( arccos[1/sqrt(x)] )

Thanks in advance - May 13th 2007, 11:53 PMqbkr21Re: