∫e^(1/2t) t^2
Use integration by parts twice.
u=t^2 ----- v=e^(1/2t)
How do you integrate ∫[e^(1/2t) t^2]?
Is this done by parts? I've been away from calculus for about 7 years now...I've been looking through my Calc book but I can't remember very much of this stuff and how to decide what to use to integrate what.
Thanks for the help, how does this look?
1st time by parts:
u = t^2 dv = e^(1/2t) dt
du = 2t dt v = 2e^(1/2t)
uv - Int v du
= (t^2)(2e^(1/2t)) - Int [2e^(1/2t)](2t) dt
2nd time by parts:
u = 2t dv = 2e^(1/2t)
du = 2t dt v = 4e^(1/2t) dt
uv - Int v du
= (2t)(4e^(1/2)) - Int (4e^(1/2t))*2 dt
= (2t)(4e^(1/2)) - 8*(2e^(1/2t)
= (2t)(4e^(1/2)) - 16 e^(1/2t)
Also, sorry but does anyone know where I can find the explanation page? I'm trying to figure out how to display the Integral sign and exponents properly.
Many thanks
Look around here: http://www.mathhelpforum.com/math-help/latex-help/Originally Posted by crabchef
Good luck