Essentially, I need to find the surface area of a given water tower for a Calculus AB project:Because no diameters or radii are given, I am having trouble finding a good starting point. Any help or insights would be greatly appreciated...

- The spherical top holds a little over 54,000 gallons of water, the base of the top is 60 feet above the ground and the diameter of the supporting column is one-third the radius of the sphere. The base of the supporting column flares out like a cone so that the diameter of the bottom is equal to the radius of the sphere; this bottom section is 15 feet tall. Likewise, the connection between the support and the sphere flares out to a diameter equal to two-thirds the radius of the sphere and is 10 feet tall.

-Simon