I would convert the gallons into cubic metres, then take a look at V = (4/3)(pi)(r^3). That should give you a radius to work with. It's always the simple stuff .

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- May 13th 2007, 06:24 PM #1

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## H20 in the S-K-Y

Essentially, I need to find the surface area of a given water tower for a Calculus AB project:

- The spherical top holds a little over 54,000 gallons of water, the base of the top is 60 feet above the ground and the diameter of the supporting column is one-third the radius of the sphere. The base of the supporting column flares out like a cone so that the diameter of the bottom is equal to the radius of the sphere; this bottom section is 15 feet tall. Likewise, the connection between the support and the sphere flares out to a diameter equal to two-thirds the radius of the sphere and is 10 feet tall.

-Simon

- May 13th 2007, 11:21 PM #2

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- May 14th 2007, 05:56 PM #3

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- May 15th 2007, 01:57 PM #4

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