Cartesian Polar Integral Converstion

**de20** · Jun 27th 2010, 06:07 PM

PLZ HELP! appreciations

change the cartesian integral into polar integral then evaluate the polar integral
$Cartesian Polar Integral Converstion-math.jpg$ 0<y<6 0<x<y xdxdy

**Prove It** · Jun 27th 2010, 06:28 PM

I don't see any reason to change this integral to a polar integral...

**Jhevon** · Jun 27th 2010, 06:35 PM

I agree with Prove It. But if this is just your professor being annoying and wants you to use Polar coordinates even when it is unnecessary, you can recall that for Polar coordinates

$x \mapsto r \cos \theta$

$y \mapsto r \sin \theta$

and

$dx~dy \mapsto r ~dr~d \theta$

Hopefully you can use this to figure it out.

**de20** · Jun 27th 2010, 06:37 PM

it is required bythe book ..........i wouldnt want to change it ether if i wasnt required to

**de20** · Jun 27th 2010, 07:11 PM

can u atleast show me the bounds of integrations pleasae? i was wondering if i can have 0<r<root72 sinthata or 0<r<rsin thata

**Jhevon** · Jun 27th 2010, 07:24 PM

Hopefully you can see that $\frac {\pi}4 \le \theta \le \frac {\pi}2$

Now, you know that $0 < y < 6$

Switch to polar:

$0 < r \sin \theta < 6$

which means

$0 < r < 6 \csc \theta$

**de20** · Jun 27th 2010, 07:49 PM

Originally Posted by jhevon

hopefully you can see that $\frac {\pi}4 \le \theta \le \frac {\pi}2$

now, you know that $0 < y < 6$

switch to polar:

$0 < r \sin \theta < 6$

which means

$0 < r < 6 \csc \theta$

thank you!

Thread: Cartesian Polar Integral Converstion

LinkBack

Thread Tools

Display

Cartesian Polar Integral Converstion

Similar Math Help Forum Discussions

Transforming integral in cartesian coordinates to polar coordinates

[SOLVED] HowTo:upper and lowerlimit of integral from Cartesian coordinate to polar coordinate?

Convert an integral from Cartesian to Polar coordinates and evaluate it.

Polar to cartesian

cartesian and polar

Search Tags