I'm curious as to how you got to calculus 1 without knowing how to deal with fractions.

Firstly,

In general: a/(b + c) IS NOT EQUAL TO a/b + a/c

so 1/(1+e^-x) IS NOT THE SAME AS 1/1 + 1/e^-x

we can only split up a fraction in that way if we have a single term in the denominator.

for example, (a + b)/c = a/c + b/c

so first thing you need to do is review fractions.

Secondly,

dy/dx means "the derivative of y with respect to x" there is no y here. you wan dv/dx, "the derivative of v with respect to x"

Now to your problem

v = 1/(1+e^-x) ............change this in terms of an exponent

=> v = (1 + e^-x)^-1 ......now we proceed by the Chain rule

Note: Chain Rule

[f(g(x))]' = f'(g(x))*g'(x)

So, v = (1 + e^-x)^-1

=> dv/dx = -1(1 + e^-x)^-2 *(1 + e^-x)'

.........= -(1 + e^-x)^-2 * (-e^-x)

.........= (e^-x)(1 + e^-x)^-2

.........= (e^-x)/[(1 + e^-x)^2]