Do you know how to compute the gradient? The f you have doesn't have F as its gradient (but its really close).
(a) Find a function such that , and (b) use part (a) to evaluate along the given curve C.
C:
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MY work:
(a)
Check if it's conservative or not:
and
It is conservative.
. So , which means
Therefore,
Is that correct so far? I'm kind of lost here. I'm confused what I'm supposed to do with the whole thing.
This is probably a typo- you dropped the ^2 on the x.
Now, what exactly IS the "given curve c"? You give parametric equations for a curve but no beginning and ending values for t.
If you have such values, calculate the corresponding beginning and ending values for x and y, calculate F(x,y) for those values and subtract, just like you do for integrals on the real numbers. Of course, the constant, K, will cancel out when you do that. That is why mr fantastic said "You can make an arbitrary choice of K= 0".
Is that correct so far? I'm kind of lost here. I'm confused what I'm supposed to do with the whole thing.[/QUOTE]