Math Help - Finding the first partial derivatives of f(x,y) = x²y sin(xy)

1. Finding the first partial derivatives of f(x,y) = x²y sin(xy)

Q. Find the first partial derivatives of f(x,y) = x²y sin(xy)

Here's my approach:

Partial with respect to x = 2xy sin (xy) + x²y² cost (xy)
Partial with respect to y = x² sin (xy) + x³y cos (xy)

Does this seem right?

2. Originally Posted by keysar7
Q. Find the first partial derivatives of f(x,y) = x²y sin(xy)

Here's my approach:

Partial with respect to x = 2xy sin (xy) + x²y² cost (xy)
Partial with respect to y = x² sin (xy) + x³y cos (xy)

Does this seem right?
Looks right to me.

3. Yes u are you are right.