Q. Find the first partial derivatives of f(x,y) = x²y sin(xy) Here's my approach: Partial with respect to x = 2xy sin (xy) + x²y² cost (xy) Partial with respect to y = x² sin (xy) + x³y cos (xy) Does this seem right?
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Originally Posted by keysar7 Q. Find the first partial derivatives of f(x,y) = x²y sin(xy) Here's my approach: Partial with respect to x = 2xy sin (xy) + x²y² cost (xy) Partial with respect to y = x² sin (xy) + x³y cos (xy) Does this seem right? Looks right to me.
Yes u are you are right.
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