Good morning,

I am doing a quick review and going over some of my completed problems here. I have the following:

$\displaystyle

\displaystyle{\frac{\lim}{x\rightarrow0}\frac{a^x-1}{x}}

$

Applying $\displaystyle L'H$ I got

$\displaystyle

\displaystyle{\frac{\lim}{x\rightarrow0}\frac{\ln( a)a^x}{1}}

$

Here's the problem, I don't remember why I went from $\displaystyle a^x$to $\displaystyle ln(a)a^x$.

It's something simple, right?