Integral of e^x*cos(2x)
Would I use the u,du,dv,v method? And set dv = e^x, and U=Cos(2x) ?
Moving over the last part we have:
Combining like terms on the left side gives:
And finnally, buy dividing by the constant plus one:
And thats my hint, take it for what its worth.
Ok, first off, how do I write in the proper math formulas? (mine always looks so messy
I've almost gotten to the end of the problem right now it's looking like:
Integral of (e^x)cos(2x) = cos(2x)(e^x) + 2(sin(2x)(e^x) - 2[integralsign](e^x)cos(2x))
So I have gotten back to the original function but I'm a little confused about how to distribute the 2, does the 2 go in front of both the sin(2x) and the (e^x)?? Thanks