Originally Posted by

**nautica17** I did this problem and I'm hoping it's correct, but I want to be sure as I have no answer key at hand. It's a fun little problem that involves Simpson's rule. Here it goes:

I am given that (b-a)/n = 200ft where n = 8.

So here is my calculus using Simpson's where I calculate the area of the lake:

(200/3) * (0 + 4(200) + 2(400) + 4(600) + 2(800) + 4(1000) + 2(1200) + 4(1400) + 1600) = 1,280,000 ft^2

Given average depth was 20ft. So...

20 * 1,280,000 = 25,600,000 ft^3 = volume

1 fish per 1000 cubic feet

25,600,000 / 1000 = 25,600 fish in the lake.

25% of 25,600 = 6400 = the amount of fish that need to remain.

75% of 25,600 = 19,200 = the amount of fish to be fished out.

Average catch is 20 fish per person, so..

19200 / 20 = 960 licenses per season allowed = answer to original question.

So again.. I'm wondering if I did this right. I hope I didn't screw up on the calc portion.