1) Show
2) North South distance d-metre between the south semi circle boundary and the cubic model of the wall can be found using:
a) Domain of . Find and
I have attempted these and I am stuck. Any help/hints will be appreciated.
1) Show
2) North South distance d-metre between the south semi circle boundary and the cubic model of the wall can be found using:
a) Domain of . Find and
I have attempted these and I am stuck. Any help/hints will be appreciated.
This makes no sense at all. I can assume that the graph of y= f(x) is the curve that, in your picture, looks like two straight lines but you haven't specified any coordinate system. Where are x and y measured from? If we assume that (0, 0) is at the point on the left where the curves seems to end and that the x and y components are the distances in meters we still have only that y(0)= 0 and that y(60)= 40. What reason do we have to think that the curved wall comes back to the base so that y(90)= 0?
2) North South distance d-metre between the south semi circle boundary and the cubic model of the wall can be found using:
a) Domain of . Find and
I have attempted these and I am stuck. Any help/hints will be appreciated.