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Math Help - applications of differentiation #2

  1. #1
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    applications of differentiation #2

    The diagram below is of two parabola (ASD and BTD) joined together smoothly.
    a) Find the value of y1.
    Consider the points (27.5, 19.5)and (27,y1)
    \frac{27}{27.5} = \frac{y}{19.5}
    y1 = \frac{1053}{55} = 19\frac{8}{55}

    Is this correct? Sorry don't know how to use latex to make it all look neat.

    b) Parabola BTD contains the point D and has a zero gradient. Show that its equation is y = \frac{-2}{99}(x-60)^2 + 40
    c) Use calculus to find the gradient of the parabola BTD at point 0.
    d) Hence find the equation of the parabola ASD containing point A and joined smoothly to parabola BTD at point D. Curves joined smoothly at a point have the same gradient that that point.

    Please keep any working out as simple as possible so that I can understand. Any help regarding these questions will be appreciated!
    Attached Thumbnails Attached Thumbnails applications of differentiation #2-untitled3.jpg  
    Last edited by mr fantastic; June 19th 2010 at 01:52 PM. Reason: Implement laTEX
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  2. #2
    Grand Panjandrum
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    That is incomprehensible, try rewording and/or including any missing information.

    CB
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