Introductory Calculus Question (trig limit)

• May 11th 2007, 06:01 PM
turillian@gmail.com
Introductory Calculus Question (trig limit)
limit as x approaches zero of (1-cos^4(x ))/(sin2x)^2 = ??

I can get to
(1-cos^4(x ))/(sin2x)^2 = (1-cos^2x)(1+cos^2x) / ((2sinxcosx)(2sinxcosx))
the denominator might be wrong sin2x=2sinxcosx .

Or alternatively,

(1-cos^4(x ))/(sin2x)^2 = (1+cos^2(x ))(sin^2(x ))/sin^2 (2x)

Thanks for looking. I can't get it past there. The idea is to get to a point where things can be simplified by the following:

the lim as x approaches zero of sinx/x = 1
the lim as x approaches zero of sinx=0
the lim as x approaches zero of cosx=1
• May 11th 2007, 06:28 PM
turillian@gmail.com
Thank you in advance, if you're up for it, there are a couple more I'm stuck on. This one just really bothers me because I put a couple pages and about an hour of thinking into it
• May 11th 2007, 06:31 PM
qbkr21
Re:
Some problem for your first time...:D
• May 11th 2007, 06:39 PM
turillian@gmail.com
that's ridiculously more straightforward than I was expecting.
All the textbook question in this chapter for solving limits have been of the following format (no differentiating, just rearanging):

Find the limit as x approaches zero of (sin^2xcosx)/(1-cosx)

= lim as x approaches zero of (sin^2xcosx(1+cosx))/(1-cos^2x)
= lim as x approaches zero of (cosx(1+cosx))
=1(1+1)
=2

The rest of my limit questions make a lot more sense with a differential approach :P THanks again!
• May 11th 2007, 06:40 PM
qbkr21
Re:
do you need this one work out too?

-qbkr21
• May 11th 2007, 06:43 PM
turillian@gmail.com
I think my solution is correct. I'll make another thread in the calculus forum with some other questions.