$\displaystyle \int 3e^x dx$

Printable View

- Jun 9th 2010, 12:56 PMMinino777Integrate 3 e^x
$\displaystyle \int 3e^x dx$

- Jun 9th 2010, 01:00 PMe^(i*pi)
- Jun 9th 2010, 01:01 PMDeadstar
Some rules for you to use...

$\displaystyle \int e^x dx = e^x + C$ where $\displaystyle C$ is a constant.

$\displaystyle \int a f(x) dx = a \int f(x) dx$ where $\displaystyle a$ is a constant and $\displaystyle f(x)$ is some function. - Jun 9th 2010, 01:12 PMMinino777Constant rule?
Is this the way to start:

$\displaystyle \int 3e^x dx= 3e^x + C$ - Jun 9th 2010, 01:16 PMp0oint
Although it is the correct answer, you should start by taking the constant 3 out of the integral sign.