$\displaystyle \int \sqrt t dt$ do I apply the constant rule here?
Last edited by mr fantastic; Jun 9th 2010 at 07:18 PM. Reason: Re-titled.
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Originally Posted by Minino777 $\displaystyle \int \sqrt t dt$ do I apply the constant rule here? Write $\displaystyle \sqrt{t} = t^{\tfrac{1}{2}}$ and use the power law
$\displaystyle \sqrt t= t^{1/2} dt$ $\displaystyle t^{1/2} dt= \frac {t^{3/2}}{3/2} + C$ I got it thanks
Originally Posted by Minino777 $\displaystyle \sqrt t= t^{1/2} dt$ $\displaystyle t^{1/2} dt= \frac {t^{3/2}}{3/2} + C$ I got it thanks Indeed although it is convention to write $\displaystyle \frac{1}{\frac{3}{2}} = \frac{2}{3}$ ie: $\displaystyle \frac{2}{3}t^{3/2} + C$
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