Hi, I have two questions: A) int_ sin[ax] cos[ax] dx B) int_ sec[sqrt(x)] /sqrt(x) Thanks
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Originally Posted by ClipsClips99 Hi, I have two questions: A) int_ sin[ax] cos[ax] dx B) int_ sec[sqrt(x)] /sqrt(x) Thanks sin(ax)*cos(ax) = (1/2)*sin(2ax) by double angle identity. Then INT (1/2)*sin(2ax) dx = (1/2) INT sin(2ax) dx If a!=0 define t=2ax that means that, -(1/2)*(1/2a)*cos(2ax)+C
Here is the second one.
Question A:
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