Thread: Integration

Hi, I have two questions:

A) int_ sin[ax] cos[ax] dx

B) int_ sec[sqrt(x)] /sqrt(x)

Thanks

Originally Posted by ClipsClips99

Hi, I have two questions:

A) int_ sin[ax] cos[ax] dx

B) int_ sec[sqrt(x)] /sqrt(x)

Thanks

sin(ax)*cos(ax) = (1/2)*sin(2ax) by double angle identity.

Then INT (1/2)*sin(2ax) dx = (1/2) INT sin(2ax) dx

If a!=0 define t=2ax that means that,

-(1/2)*(1/2a)*cos(2ax)+C

Here is the second one.

Question A: