Thread: [SOLVED] trig limits

Hi I am looking for the limit..
Lim x approach k sin(x-k)/(x^2-k^2)
I tried L`Hopitals Rule and got f `(x)=cos2k-cos2k
and g `(x) =2k-2k
which is (cos2k-cos2k)/(2k-2k)
answer is suppose to be 1/2k.

What did I miss?

Originally Posted by Neverquit

Hi I am looking for the limit..
Lim x approach k sin(x-k)/(x^2-k^2)
I tried L`Hospitals Rule and got f `(x)=cos2k-cos2k
and g `(x) =2k-2k
which is (cos2k-cos2k)/(2k-2k)
answer is suppose to be 1/2k.

What did I miss?

Don't do that L'hopital stuff....

Remember that and ..

Hi I got it now