Hi I am looking for the limit.. Lim x approach k sin(x-k)/(x^2-k^2) I tried L`Hopitals Rule and got f `(x)=cos2k-cos2k and g `(x) =2k-2k which is (cos2k-cos2k)/(2k-2k) answer is suppose to be 1/2k.
What did I miss?
Last edited by Neverquit; Jun 8th 2010 at 10:42 PM.
Reason: na
Hi I am looking for the limit.. Lim x approach k sin(x-k)/(x^2-k^2) I tried L`Hospitals Rule and got f `(x)=cos2k-cos2k and g `(x) =2k-2k which is (cos2k-cos2k)/(2k-2k) answer is suppose to be 1/2k.