# Math Help - A question (not really sure what it's called)

1. ## A question (not really sure what it's called)

Hey I'm PRETTY sure this thread belongs here. Please tell me if it doesn't

Anyway,

Question is:

$f(x) = \frac {1}{2}x^3 - 4x^2$

find $f'(-2)$

how would i go about doing this?

2. Originally Posted by jgv115
Question is:

$f(x) = \frac {1}{2}x^3 - 4x^2$

find $f'(-2)$

how would i go about doing this?
$f'(x)$ is a function that is the derivative of your original function $f(x)$. So find the derivative and plug in the value -2.

Using the power rule, $f'(x) = \frac{3}{2}x^2 - 8x$