Hey I'm PRETTY sure this thread belongs here. Please tell me if it doesn't Anyway, Question is: $\displaystyle f(x) = \frac {1}{2}x^3 - 4x^2 $ find $\displaystyle f'(-2) $ how would i go about doing this?
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Originally Posted by jgv115 Question is: $\displaystyle f(x) = \frac {1}{2}x^3 - 4x^2 $ find $\displaystyle f'(-2) $ how would i go about doing this? $\displaystyle f'(x)$ is a function that is the derivative of your original function $\displaystyle f(x)$. So find the derivative and plug in the value -2. Using the power rule, $\displaystyle f'(x) = \frac{3}{2}x^2 - 8x$ Now plug in your -2.
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