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Math Help - A question (not really sure what it's called)

  1. #1
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    A question (not really sure what it's called)

    Hey I'm PRETTY sure this thread belongs here. Please tell me if it doesn't

    Anyway,

    Question is:

    f(x) = \frac {1}{2}x^3 - 4x^2

    find f'(-2)

    how would i go about doing this?
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  2. #2
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    Quote Originally Posted by jgv115 View Post
    Question is:

    f(x) = \frac {1}{2}x^3 - 4x^2

    find f'(-2)

    how would i go about doing this?
    f'(x) is a function that is the derivative of your original function f(x). So find the derivative and plug in the value -2.

    Using the power rule, f'(x) = \frac{3}{2}x^2 - 8x

    Now plug in your -2.
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