Use Newton's method to find all roots of the equation correct to six decimal places. (x - 5)2 = ln(x) For Newton's method i've gotten up to xsub5 and i'm just wondering if i've been doing it correctly. x3= 3.82831278, x4=3.83994775, x5=3.840049459
Last edited by Esthephane; June 6th 2010 at 11:00 PM.
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Originally Posted by Esthephane Use Newton's method to find all roots of the equation correct to six decimal places. (x - 5)2 = ln(x) For Newton's method i've gotten up to xsub5 and i'm just wondering if i've been doing it correctly. x3= 3.82831278, x4=3.83994775, x5=3.840049459 1. There exists a 2nd solution at x = 6.36017 2. Convert Use the given value of the deceleration to calculate the time until the car stops. I've got Use the value of the deceleration and the time to calculate the braking distance.
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