Use Newton's method to find all roots of the equation correct to six decimal places. (x - 5)2 = ln(x)
For Newton's method i've gotten up to xsub5 and i'm just wondering if i've been doing it correctly. x3= 3.82831278, x4=3.83994775, x5=3.840049459
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Use Newton's method to find all roots of the equation correct to six decimal places. (x - 5)2 = ln(x)
For Newton's method i've gotten up to xsub5 and i'm just wondering if i've been doing it correctly. x3= 3.82831278, x4=3.83994775, x5=3.840049459
1. There exists a 2nd solution at x = 6.36017Quote:
Originally Posted by Esthephane
2. Convert
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