Hey what is the sum of the series : 1 + (1 + 2)/2! + (1 + 2 + 2^2)/3! +..... I know that the nth term is (2^n - 1)/n! . How does that help? Thanks
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I'm thinking that this series is an expansion of a simpler function, but I'm not certain. Instead, since I couldnt see the pattern, I just numerically calculated it and heres roughly what I found to be the sum: 4.6707742704716
Recall that $\displaystyle \sum_{j=0}^\infty \frac{x^j}{j!} = e^x$...
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