I'm new to all this stuff so bear with me...

I'm given $\displaystyle y =2x(8x+6) $

I need to find $\displaystyle y' $

So i do it...

$\displaystyle \frac {dx}{dy} = u\frac{dv}{dx} + v\frac {du}{dx} $

$\displaystyle 2x.\frac{d(8x+6)}{dx} + (8x+6).\frac {d2x}{dx} $

$\displaystyle 16x+12 + 16x +12 $

$\displaystyle 32x +24 $

But when I check on my calculator it says $\displaystyle 32x+12 $