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**CookieC** Find the area in the first quadrant which is bounded by xy=1, xy=4, y=x and y=2x

I attempted the question by letting u=xy and v= y then i got the equations x=u/v and y=v

I then found the jacobian which was equal to 1/v

0<u<4 and x<v<2x

I thought the limits for x was 0<u<4 and x<v<2x but the problem is the limits for the x and 2x i wasn't sure how to integrate it when the double integral was in terms of dvdu i tried using the formula x=u/v to change the limits for x and 2x but it didnt give me the right answer...which was suppose to be (3log2)/2