$\displaystyle y=x^2(e^{-2x})$

What steps would I have to do to get the derivative?

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- Jun 5th 2010, 02:15 PMkmjtHow would I derive this?
$\displaystyle y=x^2(e^{-2x})$

What steps would I have to do to get the derivative? - Jun 5th 2010, 02:18 PMmr fantastic
- Jun 5th 2010, 02:19 PMe^(i*pi)
- Jun 5th 2010, 02:50 PMkmjt
y'= (2x)(e^-2x) + (x^2)(-2e^-2x)

I haven't derived for so long, how would I simplify (Speechless) - Jun 5th 2010, 02:59 PMmr fantastic
- Jun 5th 2010, 03:13 PMAllanCuz
- Jun 5th 2010, 05:43 PMkmjt
I ended up getting xe^-2x [ 2 - 2x ] but how do I set this equal to 0 to find the intervals of increase and decrease?

- Jun 5th 2010, 06:41 PMmr fantastic